Slicy speedy solution for Xs and Os Referee by misterjmf - python coding challenges

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Slicy solution in Speedy category for Xs and Os Referee by misterjmf

def checkio(gr):
    st = ''.join(gr)
    for c in 'X','O':
        if any(c*3 in (gr[i], st[i::3]) for i in range(3)): return c
        if c*3 in (st[0::4], st[2:-1:2]): return c
    return "D"

#These "asserts" using only for self-checking and not necessary for auto-testing

May 24, 2014

Comments:

mmartsinenko on Dec. 9, 2024, 11:21 a.m.
<p>This compact solution cleverly flattens the grid into a single string (st) and uses slicing to check rows, columns, and diagonals. The use of any and generator expressions ensures concise and fast checks. However, the slicing logic can be slightly complex for less experienced programmers. It is very efficient and compact, closely matching my solution's speed.</p>

List, list and list again

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