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First solution in Clear category for Xs and Os Referee by mikra
def checkio(dane):
d = ['X'*3, 'O'*3]
for x in d:
for y in range(3):
if(x == (dane[y][0] + dane[y][1] + dane[y][2])): return x[0]
if(x == (dane[0][y] + dane[1][y] + dane[2][y])): return x[0]
if(x == (dane[0][0] + dane[1][1] + dane[2][2])): return x[0]
if(x == (dane[0][2] + dane[1][1] + dane[2][0])): return x[0]
return 'D'
Dec. 8, 2015
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