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First solution in Clear category for Worth of Words by Pavellver
VALUES = {'e': 1, 'a': 1, 'i': 1, 'o': 1, 'n': 1, 'r': 1,
't': 1, 'l': 1, 's': 1, 'u': 1, 'd': 2, 'g': 2,
'b': 3, 'c': 3, 'm': 3, 'p': 3, 'f': 4, 'h': 4,
'v': 4, 'w': 4, 'y': 4, 'k': 5, 'j': 8, 'x': 8,
'q': 10, 'z': 10}
def worth_of_words(words):
cost_list = [sum(VALUES[x] for x in i) for i in words]
return words[cost_list.index(max(cost_list))]
if __name__ == '__main__':
print("Example:")
print(worth_of_words(['hi', 'quiz', 'bomb', 'president']))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert worth_of_words(['hi', 'quiz', 'bomb', 'president']) == 'quiz'
assert worth_of_words(['zero', 'one', 'two', 'three', 'four', 'five']) == 'zero'
print("Coding complete? Click 'Check' to earn cool rewards!")
March 20, 2023
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