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First solution in Clear category for Words Order by meta77fora
def words_order(text: str, words: list) -> bool:
ls = []
text = text.split()
for i in range(len(text)):
if(text[i] in words) and (text.count(text[i]) < 2):
ls.append(text[i])
return ls == words
if __name__ == '__main__':
print("Example:")
print(words_order('hi world im here', ['world', 'here']))
# These "asserts" are used for self-checking and not for an auto-testing
assert words_order('hi world im here', ['world', 'here']) == True
assert words_order('hi world im here', ['here', 'world']) == False
assert words_order('hi world im here', ['world']) == True
assert words_order('hi world im here',
['world', 'here', 'hi']) == False
assert words_order('hi world im here',
['world', 'im', 'here']) == True
assert words_order('hi world im here',
['world', 'hi', 'here']) == False
assert words_order('hi world im here', ['world', 'world']) == False
assert words_order('hi world im here',
['country', 'world']) == False
assert words_order('hi world im here', ['wo', 'rld']) == False
assert words_order('', ['world', 'here']) == False
assert words_order("hi world world im here",["world","world"])==False
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Sept. 22, 2020
