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Index order solution in Clear category for Words Order by caldeius
def words_order(text: str, words: list) -> bool:
#word not unique in words
if len(words) != len(set(words)):
return False
#isolating the words in the text
splitted = text.split()
#indexing each word of words in the splitted text
ind = [splitted.index(word) for word in words if word in splitted]
#word not in the text if the index length doesnt match words length
if len(ind) != len(words):
return False
#checking if ind is ordered
return True if ind == sorted(ind) else False
if __name__ == '__main__':
print("Example:")
print(words_order('hi world im here', ['world', 'here']))
# These "asserts" are used for self-checking and not for an auto-testing
assert words_order('hi world im here', ['world', 'here']) == True
assert words_order('hi world im here', ['here', 'world']) == False
assert words_order('hi world im here', ['world']) == True
assert words_order('hi world im here',
['world', 'here', 'hi']) == False
assert words_order('hi world im here',
['world', 'im', 'here']) == True
assert words_order('hi world im here',
['world', 'hi', 'here']) == False
assert words_order('hi world im here', ['world', 'world']) == False
assert words_order('hi world im here',
['country', 'world']) == False
assert words_order('hi world im here', ['wo', 'rld']) == False
assert words_order('', ['world', 'here']) == False
print("Coding complete? Click 'Check' to earn cool rewards!")
May 6, 2020
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