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First solution in Clear category for Words Order by Jaime
def words_order(text: str, words: list) -> bool:
try:ver=[text.split().index(x) for x in words]
except: return False
return False if sum([words.count(x) for x in words]) !=len(words) or ver!=sorted(ver) else True
assert words_order('hi world im here',
['country', 'world']) == False
if __name__ == '__main__':
print("Example:")
print(words_order('hi world im here', ['world', 'here']))
# These "asserts" are used for self-checking and not for an auto-testing
assert words_order('hi world im here', ['world', 'here']) == True
assert words_order('hi world im here', ['here', 'world']) == False
assert words_order('hi world im here', ['world']) == True
assert words_order('hi world im here',
['world', 'here', 'hi']) == False
assert words_order('hi world im here',
['world', 'im', 'here']) == True
assert words_order('hi world im here',
['world', 'hi', 'here']) == False
assert words_order('hi world im here', ['world', 'world']) == False
assert words_order('hi world im here',
['country', 'world']) == False
assert words_order('hi world im here', ['wo', 'rld']) == False
assert words_order('', ['world', 'here']) == False
print("Coding complete? Click 'Check' to earn cool rewards!")
May 7, 2020
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