First clear solution for Word Pattern by gyahun_dash - python coding challenges

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First solution in Clear category for Word Pattern by gyahun_dash

def check_command(pattern, command):
    binpattern = '{:0={}b}'.format(pattern, len(command))
    bincommand = ''.join('1' if c.isalpha() else '0' for c in command)

    return binpattern == bincommand

May 14, 2014

Comments:

LexCavalera on May 16, 2014, 7:47 a.m.
Compact and elegant solution! Bravo!

gyahun_dash on May 16, 2014, 1:10 p.m.
Thanks!

artemrudenko on July 16, 2014, 12:52 p.m.
Awesome

gyahun_dash on July 17, 2014, 12:37 p.m.
Thank you!

ArchTauruS on Aug. 20, 2014, 10:14 a.m.
clear and elegant!

gyahun_dash on Aug. 21, 2014, 1:17 p.m.
Thank you!

mfurones on Jan. 12, 2015, 7:52 p.m.
it's great, so pretty

JMichaelis on Feb. 16, 2016, 3:19 p.m.
Nice, clear solution. The cast to <pre class='brush: python'>str(int(c.isalpha)) </pre> returns the same result as your if clause <pre class='brush: python'>'1' if c.isalpha() else '0' </pre> as True is cast to 1 and False to 0.

Paul-Yuchao-Dong on March 12, 2017, 1:14 a.m.
I like the `{:0={}b}` replacement string build-up. May I learn if there's a blogpost / tutorial that give you these knowledge / example on how to draft it like this? I tried the official doc and it was HARD. Also given the f string in Python 3.6, is there anyway I can rewrite the above in f string? Sorry for these lazy questions, but learning from documentation seems to be a bit tough for me right now.

Blizzard

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