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First (='ω'=) solution in Clear category for Weekend Counter by Magu
from datetime import date, timedelta
from itertools import count
def checkio(from_date, to_date):
cnt = 0
for d in count(0):
x = from_date + timedelta(days = d)
if x.weekday() == 5 or x.weekday() == 6: cnt += 1
if x == to_date: break
return cnt
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(date(2013, 9, 18), date(2013, 9, 23)) == 2, "1st example"
assert checkio(date(2013, 1, 1), date(2013, 2, 1)) == 8, "2nd example"
assert checkio(date(2013, 2, 2), date(2013, 2, 3)) == 2, "3rd example"
Oct. 6, 2021
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