Canonical creative solution for Verify Anagrams by veky - python coding challenges

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Canonical solution in Creative category for Verify Anagrams by veky

verify_anagrams=lambda f,s,k=lambda w:sorted(w.lower().replace(" ","")):k(f)==k(s)

May 11, 2014

Comments:

jollyca on July 22, 2014, 7:26 p.m.
I used "the lambda way" too (my first time, yey!), but I didn't think about using a second lambda to avoid code duplication. Hats off!

veky on July 22, 2014, 9:41 p.m.
lambda cult. :-D Nevermind, understanding will come later. ;-)

dannystaple on Nov. 16, 2016, 11:23 p.m.
I was looking for your solution - always an education. Didn't know you could define a lambda local to another lambda like that.

veky on Nov. 17, 2016, 6:41 a.m.
Education is my main motive, yes. :-) That's just a default argument: <pre class='brush: python'>def verify_anagrams(first, second, kanon=lambda w:sorted(w.lower().replace(" ","")): return kanon(first) == kanon(second) def verify_anagrams(first, second): kanon = lambda w:sorted(w.lower().replace(" ","") return kanon(first) == kanon(second) def verify_anagrams(first, second): def kanon(word): return sorted(word.lower().replace(" ", "") return kanon(first) == kanon(second) </pre>

bsquare on Aug. 20, 2019, 11:13 a.m.
Hey Veky. Nice solution as often. Clear and concise. Coming back from holidays I'll be able to keep on enjoying checkio 😊

mlahor on Sept. 30, 2019, 10:18 a.m.
Very cool succinct solution (reviewing for a quest)

Look up in the Dict()

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