First clear solution for Verify Anagrams by michal123 - python coding challenges

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First solution in Clear category for Verify Anagrams by michal123

def verify_anagrams(first_word, second_word):
    first_word = first_word.lower()
    second_word = second_word.lower()
    
    first_word = first_word.replace(' ', '')
    second_word = second_word.replace(' ', '')
    
    first_word = sorted(list(first_word))
    second_word = sorted(list(second_word))
    
    if first_word == second_word:
        return True
    else:
        return False
            
        

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert isinstance(verify_anagrams("a", 'z'), bool), "Boolean!"
    assert verify_anagrams("Programming", "Gram Ring Mop") == True, "Gram of code"
    assert verify_anagrams("Hello", "Ole Oh") == False, "Hello! Ole Oh!"
    assert verify_anagrams("Kyoto", "Tokyo") == True, "The global warming crisis of 3002"

Nov. 18, 2018

Comments:

kapasunka on Jan. 30, 2019, 4:42 p.m.
<p>You can do "return first<em>word == second</em>word" instead of if else structure</p>

Look up in the Dict()

0 %

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