First uncategorized solution for Verify Anagrams by Adam.Michalak - python coding challenges

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First solution in Uncategorized category for Verify Anagrams by Adam.Michalak

from itertools import groupby


def itemGroups(string):
    return [(key, len([i for i in group]))
            for key, group
            in groupby(sorted(string.lower().replace(' ', '')))]


def verify_anagrams(first_word, second_word):
    return itemGroups(first_word) == itemGroups(second_word)

if __name__ == '__main__':
    # These "asserts" using only for self-checking and not necessary for
    # auto-testing
    assert isinstance(verify_anagrams(u"a", u"z"), bool), "Boolean!"
    assert verify_anagrams(
        u"Programming", u"Gram Ring Mop") == True, "Gram of code"
    assert verify_anagrams(u"Hello", u"Ole Oh") == False, "Hello! Ole Oh!"
    assert verify_anagrams(
        u"Kyoto", u"Tokyo") == True, "The global warming crisis of 3002"

Jan. 16, 2016

Comments:

colinmcnicholl on April 30, 2021, 3:51 p.m.
Well done on solving the mission. You seem to have accumulated a lot of votes for the solution so well done for that. In your function itemGroups(string) would <pre class='brush: python'>return [(k, len(list(g))) for k, g in groupby(sorted(string.lower().replace(' ', '')))] </pre> not have been more appropriate ? itertools is a popular module, I very much like it myself, including the groupby function. However, I would not have chosen it for this application. I recommend you have a look at the in-built function Counter() in the collections module.

Look up in the Dict()

0 %

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