Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for The Angles of a Triangle by Ambulanss
import math
def checkio(a, b, c):
if a + b > c and a + c > b and b + c > a:
angle1 = math.acos( ( b ** 2 + c ** 2 - a ** 2)/(2 * b * c) )
angle2 = math.acos( ( c **2 + a ** 2 - b **2)/(2 * a *c) )
angle1 = round(math.degrees(angle1), 0)
angle2 = round(math.degrees(angle2), 0)
angle3 = 180 - angle1 - angle2
return sorted([angle1, angle2, angle3])
else:
return [0, 0, 0]
#replace this for solution
return [0, 0, 0]
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(4, 4, 4) == [60, 60, 60], "All sides are equal"
assert checkio(3, 4, 5) == [37, 53, 90], "Egyptian triangle"
assert checkio(2, 2, 5) == [0, 0, 0], "It's can not be a triangle"
Nov. 2, 2016