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First solution in Clear category for Three Words by szymonkukla1
def checkio(words):
wyrazy = words.split(" ")
i = 0
m = 0
while(i < len(wyrazy)):
if(ord(wyrazy[i][0]) >= 48 and ord(wyrazy[i][0]) <= 57):
m = 0
else:
m = m + 1
if(m == 3):
return True
i = i + 1
if(m < 3):
return False
#return True or False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 23, 2016
