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First solution in Clear category for Three Words by pawel.sydorow
def TryParseToInt(strValue):
try:
result = int(strValue)
except:
result = 0
return result
def checkio(words):
if(len(words) < 3):
return False
listWord = words.split()
for i in range(1, len(listWord) -1):
if TryParseToInt(listWord[i-1]) == 0 and TryParseToInt(listWord[i]) == 0 and TryParseToInt(listWord[i+1]) == 0:
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 7, 2016
