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First solution in Clear category for Three Words by mehWincenty
def checkio(words):
isaword = True
wordcount = 0
for letter in words:
if letter == " ":
if isaword == True:
wordcount += 1
if wordcount == 3:
return True
else:
isaword = True
wordcount = 0
if letter.isdigit():
isaword = False
if isaword == True:
wordcount += 1
if wordcount > 2:
return True
else:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 21, 2016
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