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First solution in Clear category for Three Words by m.dziardziel
def checkio(words):
bo=True
cou=0
for a in range(0,len(words)):
if 48<=ord(words[a])<=57:
bo=False
cou=0
elif ord(words[a])==32 or a==len(words)-1:
if bo==True:
cou=cou+1
if cou==3:
return True
bo=True
print(cou)
return False
Oct. 26, 2016