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First_2 solution in Clear category for Three Words by jtarnowska
def checkio(words):
numbers = "0123456789"
new_words = words.split()
words_list = []
if len(new_words) == 1:
return False
for i in range (len(new_words)):
if new_words[i].isdigit() == False:
words_list.append(new_words[i])
if len(words_list) >= 3:
return True
else:
del words_list[:]
if len(words_list) < 3:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Jan. 9, 2017