4th clear solution for Three Words by gyahun_dash - python coding challenges

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4th solution in Clear category for Three Words by gyahun_dash

import re

def checkio(words):
    return bool(re.search('\D+ \D+ \D+', words))

March 1, 2016

Comments:

Cule on Aug. 8, 2016, 10:10 a.m.
Beautiful!

davis.merrit on Aug. 27, 2016, 7:23 p.m.
Too simply with re :D

ArchTauruS on Nov. 9, 2018, 1:10 a.m.
your regex mathces '123abc def ghi'

PHANTOM0308 on April 28, 2019, 4:47 p.m.
Yeah I think only [a-zA-Z] works here.

leggewie on May 22, 2021, 5:32 p.m.
Indeed. Wouldn't re.search('\s\D+{3}', words) be simpler and "more correct"?

leggewie on May 22, 2021, 5:44 p.m.
not more without taking into account the possibility of three words at the beginning of the string

leggewie on May 22, 2021, 5:56 p.m.
My <a href="https://py.checkio.org/mission/three-words/publications/leggewie/python-3/elegant-advanced-regexp-solution/">improved version</a>.

leggewie on May 22, 2021, 6:12 p.m.
Even the improved version was still faulty (as you can see, RegEx are elegant and powerful, but it's easy to make mistakes and introduce bugs). Hence, another <a href="https://py.checkio.org/mission/three-words/publications/leggewie/python-3/elegant-advanced-and-robust-regexp-solution/">improvement</a> for robustness.

Pactp on April 12, 2023, 8:28 a.m.
how about: re.search('(\s\D+){3}\s', ' ' + words + ' ')

leggewie on May 22, 2021, 6:23 p.m.
Actually, no, this is not a problem per the preconditions: "Precondition: [...] There are no mixed words (letters and digits combined)."

krzysztofrrr on May 3, 2020, 10:03 p.m.
very nice

zenek.spb on June 16, 2020, 9:40 a.m.
Very clear! Good job!

russrage on Dec. 14, 2020, 2:20 a.m.
Excellent

Striga on Dec. 16, 2020, 5:17 p.m.
Wow... Nice use of regex.. Keep up the good work!

Striga on Dec. 16, 2020, 5:19 p.m.
Wow… Nice use of regex… Keep up the good work!

koborC on Dec. 31, 2020, 9:20 a.m.
I'm not sure which of "/d" or "[a-zA-Z]" is better to match character w/o numbers, for task description is not accurate.

ChromeBrainer on April 6, 2021, 5:40 a.m.
can someone explain this solution

leggewie on May 22, 2021, 5:47 p.m.
I am no RegEx guru <ul> <li><a href="http://www-db.deis.unibo.it/courses/TW/DOCS/w3schools/jsref/jsref_regexp_digit_non.asp.html">\D</a> looks for non-digit characters</li> <li><a href="http://www-db.deis.unibo.it/courses/TW/DOCS/w3schools/jsref/jsref_regexp_onemore.asp.html">+</a> looks for 1 or more occurrences</li> </ul> So, what this does is to look in the words variable for a bunch of letters, followed by a space, followed by a bunch of letters, followed by a space, followed by a bunch of letters. If there is a match the bool returns true. The solution is actually faulty, though, as ArchTauruS correctly <a href="https://py.checkio.org/mission/three-words/publications/gyahun_dash/python-3/4th/share/517356748fe5f36f7d2a81e35bd8b042/#comment-66692">pointed out</a>.

alterGNU on July 22, 2021, 6:22 p.m.
that's a pretty nice solution ^^

mr_vads on Aug. 16, 2021, 6:31 p.m.
nice solution! still, this might be more flexible regexp: <pre class='brush: python'>(\D+\s){2}\D+ </pre>

jsg-inet on Sept. 6, 2021, 2:04 p.m.
Wow! I like the simplicity of this solution! I have learn something new with it! Thank you!

orniton on Dec. 19, 2021, 9:20 p.m.
I just discovered the beauty of RegEx for me and I must say, it is awesome. Just like this example.

fiftigreen on April 25, 2022, 8:51 a.m.
Nice solution! Keep going in the same direction!

jv43 on Feb. 22, 2023, 4:29 a.m.
Wow! I like the simplicity of this solution! I have learn something new with it! Thank you!

Adrian_Sanz_Wallace on March 14, 2023, 4:26 p.m.
This solution would accept words like "... ... ..." or "@@ # ()", which are not actually words as the statement asks for.

Pactp on Sept. 18, 2023, 9:18 a.m.
Nice trick. One line solution with re.

o.kovalev on June 24, 2024, 5:29 a.m.
Well done. Happy coding

jrchionis on Aug. 22, 2024, 8:55 p.m.
Someday I'll actually get around to learning regular expressions >__<

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