Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Uncategorized category for Three Words by elVato
def checkio(words):
words_list = words.split()
c = 0
for i in words_list:
if i.isalpha():
c += 1
else:
c = 0
if c == 3:
return True
return False
Nov. 7, 2015
