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First solution in Clear category for Three Words by dm.palczak
def checkio(words):
count = 0
for word in words.split(' '):
if word[0].isdigit():
count = 0
else:
count += 1
if count == 3:
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(u"Hello World hello") == True, "Hello"
assert checkio(u"He is 123 man") == False, "123 man"
assert checkio(u"1 2 3 4") == False, "Digits"
assert checkio(u"bla bla bla bla") == True, "Bla Bla"
assert checkio(u"Hi") == False, "Hi"
Dec. 4, 2016
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