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3 words solution in Clear category for Three Words by Yeti
def checkio(words):
licz=0
litera=True
for word in words:
if word.isdigit():
licz=0
litera=False
elif word==' ' and litera==True:
licz+=1
litera=True
if word.isdigit()==False:
litera=True
if licz>2:
return True
print(licz)
if litera==True:
licz+=1
if licz>2:
return True
else: return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 18, 2016