Second clear solution for Three Words by Wakko_Warner - python coding challenges

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Second solution in Clear category for Three Words by Wakko_Warner

def checkio(words):
    counter = 0
    result = False
    for word in words.split():
        if word.isalpha():
            counter += 1
            if counter >= 3: result = True
        else:
            counter = 0
        
    return result

Nov. 19, 2020

Comments:

eyes.in.head on Dec. 30, 2020, 6:08 p.m.
<blockquote> <p>if counter >= 3: result = True</p> </blockquote> <p>You can return True from here</p>

Strings and Integers

0 %

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