First creative solution for Three Words by Tubis - python coding challenges

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First solution in Creative category for Three Words by Tubis

checkio=lambda x:"www" in "".join('w' if w.isalpha() else 'd' for w in x.split())

Feb. 20, 2014

Comments:

nickie on Feb. 20, 2014, 6:58 p.m.
Alright, same idea. I missed the "'www' in" part, which is much nicer than my "find". You missed how to avoid the "if...else" part. Well done! Combining our puzzles, we get: <pre class='brush: python'>checkio=lambda t:'T'*3in"".join(str(w.isalpha())[0]for w in t.split()) </pre>

shiracamus on Feb. 27, 2014, 3:22 a.m.
A little shorter: <pre class='brush: python'>checkio=lambda x:"www" in "".join('dw'[w.isalpha()] for w in x.split()) </pre>

PavloTaiko on May 9, 2014, 12:41 p.m.
Cool bro

nptwz on Aug. 15, 2014, 2:06 a.m.
cool

jamestotle on Sept. 2, 2014, 1:56 p.m.
same idea, but I use str(w.isalpha())

wuhuarui1992 on April 27, 2016, 8:59 p.m.
cool

leggewie on May 22, 2021, 5:23 p.m.
Wow! but good luck to the guy who takes over your job in two years and has to support that code, hahaha!

CDG.Axel on March 23, 2023, 10:46 a.m.
Slightly shorter :) <pre class='brush: python'>checkio=lambda s:'111' in ''.join(str(+x.isalpha()) for x in s.split()) # and with space abusing checkio=lambda s:'111'in''.join(str(+x.isalpha())for x in s.split()) </pre>

zeixes on July 8, 2024, 2:02 p.m.
Nice one_liner and realy creative. But it works with all volume of data.

Strings and Integers

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