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isalpha solution in Clear category for Three Words by Rudeboyz_Squad
def checkio(words: str) -> bool:
words = words.split()
l = len(words)-2
for i in range(l):
if all([words[i].isalpha(),words[i+1].isalpha(),words[i+2].isalpha()]):
return True
return False
April 4, 2019
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