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First solution in Clear category for Three Words by PawelMartyniuk
def checkio(words):
numberofwordsinrow = 0
if words[0].isalpha() == True:
numberofwordsinrow += 1
n = 1
while (n < len(words)):
if (words[n].isalpha() == True) and (words[n - 1] == ' '):
numberofwordsinrow += 1
if (words[n].isdigit() == True) and (words[n - 1] == ' ' and numberofwordsinrow<3):
numberofwordsinrow = 0
n += 1
if (numberofwordsinrow >= 3):
return True
else:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 23, 2016
