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First solution in Clear category for Three Words by Michal_Cichy
def checkio(words):
slowa=0
good=1
for i in words:
if i==" ":
if good:
slowa+=1
if slowa>=3:
return True
good=1
if i in "1234567890":
slowa=0
good=0
if good:
slowa+=1
if slowa>=3:
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 30, 2016
