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First solution in Uncategorized category for Three Words by MedykMatyk
def checkio(words):
counter = 0
if(not words[0].isdigit()): counter+=1
for i in range(1,len(words)):
if(not words[i].isdigit() and words[i-1]==' '):
counter+=1
elif(words[i].isdigit()): counter=0
if(counter==3):
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Nov. 5, 2017
