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all + [i:i + 3] solution in Clear category for Three Words by Lemmi
def checkio(words):
words = words.split()
for num in range(len(words) - 2):
if all(elem.isalpha() for elem in words[num: num + 3]):
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
July 22, 2017
