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First solution in Clear category for Three Words by KikeKeiDash
import string
def checkio(words: str) -> bool:
cont = 0
words = words.split() # slicing the string in a list
for word in words:
if word.isalpha(): # checking if each element in words is a string
cont+=1 # if is a string we add one to "cont"
if cont == 3: # if cont=3 there are 3 successive strings
return True
else: # if some element in "words" isn't a string we put cont=0
cont = 0
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print('Example:')
print(checkio("Hello World hello"))
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Feb. 18, 2019
