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First solution in Clear category for Three Words by KarolinaK
def checkio(words):
word=""
succession=0
win=False
for letter in words:
if(letter!=' '):
word+=letter
else:
if not word.isnumeric():
succession+=1
else:
succession=0
word=""
if succession==3:
win=True
break
if not word.isnumeric():
succession+=1
else:
succession=0
if succession==3:
win=True
return win
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 17, 2016
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