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First solution in Clear category for Three Words by DianaT
def is_word(x):
return 1 if x.isalpha() else 0
def checkio(words):
word_list = [is_word(i) for i in words.split()]
consecutive_words = [sum(word_list[i:i + 3])
for i in range(len(word_list))
if word_list[i]]
return any([True for i in consecutive_words if i >= 3])
# These "asserts" using only for self-checking and not necessary for
# auto-testing
if __name__ == '__main__': # pragma: no cover
assert checkio(u"Hello World hello") is True, "Hello"
assert checkio(u"He is 123 man") is False, "123 man"
assert checkio(u"1 2 3 4") is False, "Digits"
assert checkio(u"bla bla bla bla") is True, "Bla Bla"
assert checkio(u"Hi") is False, "Hi"
Dec. 6, 2016
