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First solution in Clear category for Three Words by Cyrus490
def checkio(words):
isword = [i.isalpha() for i in words.split()]
sets_of_3 = [isword[i:i+3] for i in range(len(isword) - 2)]
return any([all(m) for m in [n for n in sets_of_3]])
June 26, 2020
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