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First solution in Clear category for Three Words by Alex6766
def checkio(words):
m=0
k=0
n=0
words=words+' '
l=len(words)
while m<=l-1:
if words[m]==' ':
rez=words[n:m]
n=m+1
if ('a'<=rez[0]<='z') or ('A'<=rez[0]<='Z'):
k=k+1
else:
k=0
if k==3:
return True
break
m=m+1
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 20, 2016
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