Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
One Liner solution in Speedy category for The Nearest Square Number by dobyvillanueva
def nearest_square(number):
return round(number**0.5)**2
if __name__ == '__main__':
print("Example:")
print(nearest_square(8))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert nearest_square(8) == 9
assert nearest_square(13) == 16
assert nearest_square(24) == 25
assert nearest_square(9876) == 9801
print("Coding complete? Click 'Check' to earn cool rewards!")
May 11, 2018
