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Simple Use of Dictionary solution in Clear category for The Most Frequent by mithilkotak
def most_frequent(data: list[str]) -> str:
# your code here
counts={}
for string in data:
counts|={string:data.count(string)}
return [string for string in counts.keys() if counts[string]==max(counts.values())][0]
print("Example:")
print(most_frequent(["a", "b", "c", "a", "b", "a"]))
assert most_frequent(["a", "b", "c", "a", "b", "a"]) == "a"
assert most_frequent(["a", "a", "bi", "bi", "bi"]) == "bi"
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Sept. 8, 2022
