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Using collections.Counter.most_common() solution in Speedy category for The Most Frequent by H0r4c3
from collections import Counter
def most_frequent(data: list) -> str:
"""
determines the most frequently occurring string in the sequence.
"""
string_counts = Counter(data)
return string_counts.most_common()[0][0]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
print('Example:')
print(most_frequent([
'a', 'b', 'c',
'a', 'b',
'a'
]))
assert most_frequent([
'a', 'b', 'c',
'a', 'b',
'a'
]) == 'a'
assert most_frequent(['a', 'a', 'bi', 'bi', 'bi']) == 'bi'
print('Done')
April 24, 2022
