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First solution in Clear category for The Most Frequent by Darka
def most_frequent(data: list) -> str:
"""
determines the most frequently occurring string in the sequence.
"""
counter=0
maxi=0
for i in range(len(data)):
if(data[i]!=0):
word=data[i]
counter+=1
for j in range(i+1, len(data)):
if(data[j]==word):
counter+=1
data[j]=0
if counter > maxi:
maxi=counter
answer=word
counter=0
return answer
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
print('Example:')
print(most_frequent([
'a', 'b', 'c',
'a', 'b',
'a'
]))
assert most_frequent([
'a', 'b', 'c',
'a', 'b',
'a'
]) == 'a'
assert most_frequent(['a', 'a', 'bi', 'bi', 'bi']) == 'bi'
print('Done')
Nov. 29, 2018
