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First (This is usually the last day of the year ) solution in Clear category for The Most Frequent Weekdays by wo.tomasz
import datetime
import calendar
def most_frequent_days(a):
dl = [datetime.date(a, 12, 30), datetime.date(a, 12, 31)]
if not calendar.isleap(a):
dl.pop(0)
dl.sort(key= lambda w: w.weekday())
return [d.strftime("%A") for d in dl]
if __name__ == '__main__':
print("Example:")
print(most_frequent_days(1084))
# These "asserts" are used for self-checking and not for an auto-testing
assert most_frequent_days(1084) == ['Tuesday', 'Wednesday']
assert most_frequent_days(1167) == ['Sunday']
assert most_frequent_days(1216) == ['Friday', 'Saturday']
assert most_frequent_days(1492) == ['Friday', 'Saturday']
assert most_frequent_days(1770) == ['Monday']
assert most_frequent_days(1785) == ['Saturday']
assert most_frequent_days(212) == ['Wednesday', 'Thursday']
assert most_frequent_days(1) == ['Monday']
assert most_frequent_days(2135) == ['Saturday']
assert most_frequent_days(3043) == ['Sunday']
assert most_frequent_days(2001) == ['Monday']
assert most_frequent_days(3150) == ['Sunday']
assert most_frequent_days(3230) == ['Tuesday']
assert most_frequent_days(328) == ['Monday', 'Sunday']
assert most_frequent_days(2016) == ['Friday', 'Saturday']
print("Coding complete? Click 'Check' to earn cool rewards!")
Jan. 3, 2021
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