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First 2 lines solution in Clear category for The Most Frequent Weekdays by dashrek1
import calendar
most_frequent_days=lambda a: (lambda b,z:(lambda:[z[b]]+[z[b+1]] if b<6 else[z[0],z[6]])() if calendar.isleap(a) else [z[b]])(calendar.weekday(a,1,1),calendar.day_name)
Aug. 25, 2019