Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for The Cheapest Flight by freeman_lex
def cheapest_flight(costs: list, a: str, b: str) -> int:
routs = [(a, 0, costs)]
res = 0
while routs:
last, cost, flights = routs.pop(0)
avail = filter(lambda flight: last in flight, flights)
for x, y, c in avail:
target = (x, y)[x == last]
cost1 = cost + c
if target == b:
res = (cost1, min(res, cost1))[bool(res)]
continue
(flights1 := flights[:]).remove([x, y, c])
routs.append((target, cost1, flights1))
return res
if __name__ == '__main__':
print("Example:")
print(cheapest_flight([['A', 'C', 100],
['A', 'B', 20],
['B', 'C', 50]],
'A',
'C'))
# These "asserts" are used for self-checking and not for an auto-testing
assert cheapest_flight([['A', 'C', 100],
['A', 'B', 20],
['B', 'C', 50]],
'A',
'C') == 70
assert cheapest_flight([['A', 'C', 100],
['A', 'B', 20],
['B', 'C', 50]],
'C',
'A') == 70
assert cheapest_flight([['A', 'C', 40],
['A', 'B', 20],
['A', 'D', 20],
['B', 'C', 50],
['D', 'C', 70]],
'D',
'C') == 60
assert cheapest_flight([['A', 'C', 100],
['A', 'B', 20],
['D', 'F', 900]],
'A',
'F') == 0
assert cheapest_flight([['A', 'B', 10],
['A', 'C', 15],
['B', 'D', 15],
['C', 'D', 10]],
'A',
'D') == 25
print("Coding complete? Click 'Check' to earn cool rewards!")
May 9, 2023
Comments:
