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First on The best number ever solution in Creative category for The Best Number Ever by grigoriytretyakov
def checkio():
i = 16
in_hex_has_only_1_and_0 = not bool(set(hex(i)[2:]) - set('01'))
oct_twice_bigger_than_hex_in_10_radix = int(oct(i)[2:]) / int(hex(i)[2:]) == 2.0
convert_to_hex_to_str_give_two_in_bin = int(hex(i)[2:], 2)
count_of_0_in_4_times = bin(i)[2:].count('0') / hex(i)[2:].count('0')
and_2_in_power_4_give_stil_16 = 2 ** count_of_0_in_4_times
best_number = (
in_hex_has_only_1_and_0 and
oct_twice_bigger_than_hex_in_10_radix and
convert_to_hex_to_str_give_two_in_bin and
count_of_0_in_4_times == 4 and
and_2_in_power_4_give_stil_16 == 16
)
if best_number:
return i
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio(), (int, float, complex))
May 6, 2015
