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Newton solution in Clear category for Super Root by gyahun_dash
from math import log, log10
def super_root(number):
x = log10(number) + 1 # initial guess in [1, 11]
while True:
y = x ** x
diff = y - number
if abs(diff) < 0.001: return x
x -= diff / (y * (1 + log(x)))
July 3, 2014
