while and sum clear solution for Sum of Digits by kdim - python coding challenges

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while and sum solution in Clear category for Sum of Digits by kdim

def sum_digits(num: int) -> int:
    while num > 9:
        num = sum(int(n) for n in str(num))
    return num


print("Example:")
print(sum_digits(38))

assert sum_digits(38) == 2
assert sum_digits(0) == 0
assert sum_digits(10) == 1
assert sum_digits(132) == 6
assert sum_digits(232) == 7
assert sum_digits(811) == 1
assert sum_digits(702) == 9

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Sept. 27, 2022

Comments:

jakubbortlik on Nov. 30, 2022, 3:46 p.m.
+4 Nice clear solution! I used recursion instead and tested if `len(str(num)) > 1`, but using `while` and simple `num > 9` seems more readable!

wo.tomasz on March 26, 2023, 12:46 p.m.
I think it's better to use the // operator instead of casting to str

Strings Theory

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