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my itertools solution in Speedy category for Sum Consecutives by andreirozgkob164
def sum_consecutives(a):
res = [sum(i[1]) for i in __import__('itertools').groupby(a)]
return res
if __name__ == '__main__':
print("Example:")
print(list(sum_consecutives([1, 1, 1, 1])))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(sum_consecutives([1, 1, 1, 1])) == [4]
assert list(sum_consecutives([1, 1, 2, 2])) == [2, 4]
assert list(sum_consecutives([1, 1, 2, 1])) == [2, 2, 1]
assert list(sum_consecutives([3, 3, 3, 4, 4, 5, 6, 6])) == [9, 8, 5, 12]
assert list(sum_consecutives([1])) == [1]
assert list(sum_consecutives([])) == []
print("Coding complete? Click 'Check' to earn cool rewards!")
May 15, 2023
