Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
regex only solution in Clear category for Striped Words by skar123
import re
V = "AEIOUY"
C = "BCDFGHJKLMNPQRSTVWXZ"
def checkio(text):
pat = re.compile(f"\\b((?:(?:[{V}][{C}])+[{V}]?)|(?:(?:[{C}][{V}])+[{C}]?))\\b", re.I)
return len(pat.findall(text))
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("My name is ...") == 3, "All words are striped"
assert checkio("Hello world") == 0, "No one"
assert checkio("A quantity of striped words.") == 1, "Only of"
assert checkio("Dog,cat,mouse,bird.Human.") == 3, "Dog, cat and human"
April 10, 2019
