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First solution in Clear category for Striped Words by kvyatkovsky89
VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"
import re
def checkio(text):
return len(re.findall(r'\b(?:[%s]{1}[%s]{1})+[%s]?\b|\b(?:[%s]{1}[%s]{1})+[%s]?\b'%
(VOWELS,CONSONANTS,VOWELS, CONSONANTS, VOWELS, CONSONANTS), text, flags=re.IGNORECASE))
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("My name is ...") == 3, "All words are striped"
assert checkio("Hello world") == 0, "No one"
assert checkio("A quantity of striped words.") == 1, "Only of"
assert checkio("Dog,cat,mouse,bird.Human.") == 3, "Dog, cat and human"
April 15, 2019
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