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First solution in Clear category for Striped Words by DahliaSR
import re
from string import ascii_lowercase
VOWELS = "aeiouy"
def checkio(text):
words = re.findall(re.compile(r'\b[^\W\d]{2,}\b'), text.lower())
transl_to = ''.join('1' if char in VOWELS else '0' for char in ascii_lowercase)
translator = str.maketrans(ascii_lowercase, transl_to)
translated_words = (word.translate(translator) for word in words)
count = 0
for word in translated_words:
if re.search(r'(00|11)', word):
count += 1
return len(words) - count
if __name__ == '__main__':
assert checkio("My name is ...") == 3, "All words are striped"
assert checkio("Hello world") == 0, "No one"
assert checkio("A quantity of striped words.") == 1, "Only of"
assert checkio("Dog,cat,mouse,bird.Human.") == 3, "Dog, cat and human"
May 31, 2016
