2-liner: h#e#l#p creative solution for Stressful Subject by przemyslaw.daniel - python coding challenges

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2-liner: h#e#l#p solution in Creative category for Stressful Subject by przemyslaw.daniel

def is_stressful(t, r=__import__('re'), c='h#e#l#p|a#s#a#p|u#r#g#e#n#t|!!!$'):
    return t == t.upper() or bool(r.search(c.replace('#', '[^ ]*?'), t.lower()))

July 2, 2017

Comments:

juestr on May 10, 2019, 12:04 p.m.
Hmmm the regex looks a bit off, first the ? following * is redundant. More importantly matching any non space character for padding is probably not what was wanted, this would mark as stressfull words like HEmLineProof or constructs like ASpeciAlProblem.

przemyslaw.daniel on May 10, 2019, 6:25 p.m.
It's been long time but what I can remember about it is just an imperfect simplification for all testing vectors available at that time. Looking at the task description we are not actually sure what exact characters can be placed between crucial letters. We also do not know how many of them can be used. For example what should be the answer for 'h!!elp' or 'hel\@p'? Your recent solution says False, in my case is True :-)

juestr on May 11, 2019, 8:54 p.m.
Yes the description leaves much to imagination. My last solution probably errs on the very conservative side.

sorin_artem on Nov. 1, 2019, 6:55 p.m.
i don't know, is it good code or not, i need points. Btw, u r a good person, u will reach what u want, I'm sure. so good luck, random programmer from the Internet.

Strings Theory

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