straight forward clear solution for Stressful Subject by jiizzyy - python coding challenges

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straight forward solution in Clear category for Stressful Subject by jiizzyy

def is_stressful(subj):
    red_words = ['help', 'asap', 'urgent']
    
    for red_word in red_words:
        i = 0
        
        for c in subj.lower():
            if c == red_word[i]:
                i += 1
            elif i > 0 and c.isalpha() and c != red_word[i-1]:
                i = 0
                
            if i == len(red_word):
                return True
    
    return any([subj.isupper(), subj[-3:] == '!!!'])

Feb. 9, 2020

Comments:

Faibbus on May 26, 2020, 11:31 a.m.
<p>Nice finite state machine (I got lazy and used `re`).</p>

Strings Theory

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