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Recursion solution in Clear category for Speech Module by teplolog
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(number):
digits = str(number)
if number < 10:
return FIRST_TEN[number - 1]
if number < 20:
return SECOND_TEN[number - 10]
if number < 100:
tens = number // 10
rest = number - tens*10
word = OTHER_TENS[tens - 2]
return word if not rest else word + ' ' + checkio(rest)
hundreds = number // 100
rest = number - hundreds*100
word = FIRST_TEN[hundreds - 1] + ' ' + HUNDRED
return word if not rest else word + ' ' + checkio(rest)
#replace this for solution
return 'string representation of n'
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(4) == 'four', "1st example"
assert checkio(133) == 'one hundred thirty three', "2nd example"
assert checkio(12) == 'twelve', "3rd example"
assert checkio(101) == 'one hundred one', "4th example"
assert checkio(212) == 'two hundred twelve', "5th example"
assert checkio(40) == 'forty', "6th example"
assert not checkio(212).endswith(' '), "Don't forget strip whitespaces at the end of string"
June 12, 2014
